Task 1: Analyzing Inorganic Chemical Compounds
Solution Task 1
- Flame test
Procedure
- Dip a platinum or nichrome wire in a concentrated hydrochloric acid and then hold it into a hot Bunsen flame
- When the nichrome wire is clean up, then dip it into the amount of solid you are testing
- Place the wire back to the flame again
Observation and presence of ions
Flame colour
Metals presences in the solution
Red
Lithium
Strong persisted orange
Sodium
Lilac
Potassium
Reddish-violet
Rubidium
Blue – violet
Caesium
Orange –red
Calcium
Blue-green
Copper
Greyish- white
Lead
Pale-green
Barium
- Sulphate test and sulphite
Procedure
- To 2.0 cm3 of sodium sulphate in a test tube, add 2.0 cm3 of barium chloride or nitrate solution
- To the mixture add 2 cm3 of dilute hydrochloric acid or dilute nitric (V) acid
- Repeat the above two procedure using a solution of sodium sulphite
Observation and conclusion
A white precipitate, insoluble in the dilute acid was observed, this indicate the presence of sulphate ions A white precipitate which dissolves in dilute acid with production of a colourless gas which turns filter paper soaked in acidified orange potassium chromate (VI) from orange to green indicate the presence of sulphite ions
- Carbonate test
Procedure
- Place a spatulaful of sodium carbonate in a clean test tube
- Add 2 cm3 of hydrochloric acid
- Add 2 cm3 of lime water
- Place a burning split at the open end of the test-tube
Observation and conclusion
Carbonates react with hydrochloric acid evolving carbon dioxide gas that forms a white precipitate with lime water.
The gas also extinguishes a burning wooden split
- Nitrate test
Procedure
- Place one spatulaful of sodium nitrate into a clean test tube
- Add 2 cm3 of distilled water and shake the mixture
- Add 1 cm3 of freshly prepared iron (II) sulphate and shake
- Add concentrated sulphuric acid slowly and carefully along the wall of the test tube Observation
When concentrated sulphuric acid is added to the mixture of sodium nitrate and iron (II) sulphate solution, the aciod sinks to the bottom, this because the acid is denser than the solution.The reaction produces heat
A brown ring is due to the formation of iron (II) sulphate-nitrogen (II) oxide complex ( FeSO4 .NO)
Conclusion
All nitrates gives the same result and the reaction is reffered to as the brown ring test for nitrates
- Halide test
Apparatus
Test-tubes rack, test-tube, solutions that will be used for testing that include KCl, KBr and KI, together with acidified silver nitrate solution reagent and dilute ammonia solution.
Procedure
- Put 2 cm3 of KCl solution into a test tube.
- Add 2 cm3 of silver nitrate solution.
- Note the observation and record all the changes that will take place in the test tube.
- Put 2 cm3 of KBr solution into another clean test tube and repeat procedure (ii) and (ii).
- Put 2 cm3 of KI solution into a clean third test tube and repeat procedure (ii) and (iii).
Observation
Table 1 Precipitates obtained with silver nitrate solution
Ions
Observation
chloride
Presence of white precipitate
bromide
Presence of cream precipitate
iodide
Presence of pale yellow precipitate
Task 2
You have been given six solutions. You need to classify according to their pH. You need to use Litmus paper and universal indicator to figure out whether they are acidic or basic in nature. Once you finished, then you need to use pH meter to find their pH values.
Apparatus
- Litmus paper / universal indicator
- Six different solution
- 6 test-tube
- Test –tube rack
Procedure:
- Using six red litmus paper and six blue litmus paper, dip one red and one blue litmus paper to each test tube.
- Drop a drop of universal indicator onto each solution and note the colour change.se the pH scale to write up results
Result:
Using litmus paper: acids turn a blue litmus from blue to red, bases turn a red litmus from red to blue
Task 3
Carry out Experiments to show how chromatography is used to analyse materials. You need to write the steps you have taken to demonstrate your technique and understanding.
Thin Layer Chromatography
Procedure
- Take a piece of thin layer chromatography paper.
- Cut a portion of the chromatography paper using a piece of ruler with the dimensions 10 centimeter by 8 centimeter.
- Draw a straight line across the sheet of paper at about 1.5 cm from the bottom using a pencil.
- Get and clean a piece of the glass plate. Place one drop of a samples of solutions at various parts on the glass plate.
- Mark about five small circles across the line draw in procedure (III) using a pencil.
- The solutions containing the unknown ions, mixture and known ions will be spotted on the circles drawn in procedure (V).
- Dip the broken end of the capillary tubes into one of the solutions and the tube is taped inside the dot.
- The solution is allowed to dry a re-dotting is done too. The circle is dotted for five times, and it is allowed to dry between each marking.
- To the beaker add about 5 ml of chromatography solvent (acetone) and cover it with a watch glass.
- The beaker is placed in a position to avoid it being disturbed.
- The plate/paper is placed into the undisturbed beaker and allowed to rest at the beakers bottom.
- The chromatogram is allowed to develop uninterrupted until the solvent front forms at about 1 cm of the top of the plate/paper.
- When the solvent spreads to an appropriate level, the paper is removed from the beaker and the position of the solvent front is marked using a pencil.
- The visibilities of the spots shown on the chromatogram are made possible through it being exposed on gaseous ammonia.
- Once the spots have been circled after being made visible, a ruler is used to measure the distance between the base line to the line marked as the solvent front line.The distances are then recorded.
The measures of the amount of separation of solutes in a chromatogram are expressed in terms of Rf value of each solute. The, retardation factor of Rf value is calculated by dividing the distance moved by the mobile phase into the distance traveled by the solute:
Rf =
Rf =
You have been given two unknown amino acids i.e. Lucine and Tyrosine and one unknown amino acid. You need to first find the Rf values for Lucine and T Tyrosie and the Rf value of unknown amino acid. You need to find the name of the unknown amino acids with the help of Rf data Using 3 different pipette place a drop of each amino acid and mixture X, at the appropriate position of the line
Rf for Lucine =
Rf for Tyrosine =
Rf for unknown amino acid =
The unknown amino acid is known as Phenylalanine
Task 4
Carry out experiments to identify chemicals in unknown compounds Procedure
- Mix the two unknown compounds
- Add 6M hydrochloric acid
- Filter the precipitate out
- Warm the precipitate
- To the filtrate pass over hydrogen sulphide gas
- Add a solution of ammonium (II) sulphide to the residue formed after filtering the above results
Observation and conclusion
Addition of 6M hydrochloric acid and warming the precipitate, the precipitate dissolved confirming presence of Lead (II) chloride ( PbCl2)Addition of ammonium sulphate to the residue formed when hydrogen sulphide was passed over the filtrate (procedure 5), a red-brown precipitate was formed.The blue precipitated confirmed presence of iron (III) hydroxide (FeOH3)