Probability Distribution of time between arrivals:
Time between arrivals |
Probability |
Cumulative Probability |
5 |
0.1 |
0.1 |
10 |
0.15 |
0.25 |
15 |
0.22 |
0.47 |
20 |
0.25 |
0.72 |
25 |
0.18 |
0.9 |
30 |
0.1 |
1 |
Probability distribution of attention needed:
Patient needs to see |
Probability |
Cumulative Probability |
Doctor |
0.4 |
0.4 |
Nurse |
0.35 |
0.75 |
Both |
0.25 |
1 |
The length of the patient’s visit (in minute) is defined by the following probability distributions:
Doctor |
Probability |
Cumulative Probability |
10 |
0.2 |
0.2 |
15 |
0.3 |
0.5 |
20 |
0.25 |
0.75 |
25 |
0.15 |
0.9 |
30 |
0.1 |
1 |
Nurse |
Probability |
Cumulative Probability |
5 |
0.1 |
0.1 |
10 |
0.25 |
0.35 |
15 |
0.5 |
0.85 |
20 |
0.15 |
1 |
Simulation:
Simulation Results |
|||
Element |
Element |
Statistics |
Overall |
types |
names |
Means |
|
Entrance(s) |
Door |
Objects entering process |
45 |
Objects unable to enter |
0 |
||
Service level |
1 |
||
Work Station(s) |
Clerk |
Final status |
NA |
Final inventory (int. buff.) |
0 |
||
Mean inventory (int. buff.) |
0 |
||
Mean cycle time (int. buff.) |
0 |
||
Work cycles started |
45 |
||
Fraction time working |
0 |
||
Fraction time blocked |
0 |
||
Sharon |
Final status |
NA |
|
Final inventory (int. buff.) |
0 |
||
Mean inventory (int. buff.) |
0 |
||
Mean cycle time (int. buff.) |
2 |
||
Work cycles started |
10 |
||
Fraction time working |
0 |
||
Fraction time blocked |
0 |
||
Peter |
Final status |
NA |
|
Final inventory (int. buff.) |
0 |
||
Mean inventory (int. buff.) |
0 |
||
Mean cycle time (int. buff.) |
0 |
||
Work cycles started |
9 |
||
Fraction time working |
0 |
||
Fraction time blocked |
0 |
||
Buffer(s) |
Line |
Objects leaving |
45 |
Final inventory |
0 |
||
Minimum inventory |
0 |
||
Maximum inventory |
2 |
||
Mean inventory |
0 |
||
Mean cycle time |
0 |
||
License |
Objects leaving |
10 |
|
Final inventory |
10 |
||
Minimum inventory |
0 |
||
Maximum inventory |
11 |
||
Mean inventory |
5 |
||
Mean cycle time |
108 |
||
Registration |
Objects leaving |
9 |
|
Final inventory |
4 |
||
Minimum inventory |
0 |
||
Maximum inventory |
5 |
||
Mean inventory |
2 |
||
Mean cycle time |
53 |
||
Both |
Objects leaving |
10 |
|
Final inventory |
1 |
||
Minimum inventory |
0 |
||
Maximum inventory |
3 |
||
Mean inventory |
1 |
||
Mean cycle time |
15 |
||
Served Customer |
Objects leaving |
0 |
|
Final inventory |
19 |
||
Minimum inventory |
0 |
||
Maximum inventory |
19 |
||
Mean inventory |
8 |
||
Mean cycle time |
18 |
||
Decision Point(s) |
DP |
Objects leaving |
44 |
Final inventory (int. buff.) |
0 |
||
Mean inventory (int. buff.) |
0 |
||
Mean cycle time (int. buff.) |
0 |
Therefore, overall average waiting time in the process for customers = 18 minutes
The number of customers served during the 3-hour time peak period = 44
The number of customers who have already seen the clerk at the counter but waiting to be served at the end of the 3-hour peak period = 10+9+10 = 29
The utilisation of these three employees, i.e.
o The clerk at the counter = 45/45 = 100%
o Sharon = 10/45 = 22.22%
o Peter = 9/45 = 20%
Simulation result while one resource has been added:
Simulation Results |
|||
Element |
Element |
Statistics |
Overall |
types |
names |
Means |
|
Entrance(s) |
Door |
Objects entering process |
45.08 |
Objects unable to enter |
0.00 |
||
Service level |
1.00 |
||
Work Station(s) |
Clerk |
Final status |
NA |
Final inventory (int. buff.) |
0.00 |
||
Mean inventory (int. buff.) |
0.00 |
||
Mean cycle time (int. buff.) |
0.00 |
||
Work cycles started |
45.02 |
||
Fraction time working |
0.25 |
||
Fraction time blocked |
0.00 |
||
Sharon |
Final status |
NA |
|
Final inventory (int. buff.) |
0.29 |
||
Mean inventory (int. buff.) |
0.25 |
||
Mean cycle time (int. buff.) |
2.50 |
||
Work cycles started |
10.14 |
||
Fraction time working |
0.28 |
||
Fraction time blocked |
0.25 |
||
Peter |
Final status |
NA |
|
Final inventory (int. buff.) |
0.00 |
||
Mean inventory (int. buff.) |
0.00 |
||
Mean cycle time (int. buff.) |
0.00 |
||
Work cycles started |
9.54 |
||
Fraction time working |
0.34 |
||
Fraction time blocked |
0.00 |
||
Buffer(s) |
Line |
Objects leaving |
45.02 |
Final inventory |
0.06 |
||
Minimum inventory |
0.00 |
||
Maximum inventory |
2.00 |
||
Mean inventory |
0.05 |
||
Mean cycle time |
0.21 |
||
License |
Objects leaving |
10.14 |
|
Final inventory |
10.19 |
||
Minimum inventory |
0.00 |
||
Maximum inventory |
11.09 |
||
Mean inventory |
5.34 |
||
Mean cycle time |
108.36 |
||
Registration |
Objects leaving |
9.54 |
|
Final inventory |
3.64 |
||
Minimum inventory |
0.00 |
||
Maximum inventory |
5.17 |
||
Mean inventory |
2.18 |
||
Mean cycle time |
45.34 |
||
Both |
Objects leaving |
10.14 |
|
Final inventory |
1.11 |
||
Minimum inventory |
0.00 |
||
Maximum inventory |
2.78 |
||
Mean inventory |
0.79 |
||
Mean cycle time |
14.87 |
||
Served Customer |
Objects leaving |
0.00 |
|
Final inventory |
19.00 |
||
Minimum inventory |
0.00 |
||
Maximum inventory |
19.00 |
||
Mean inventory |
8.49 |
||
Mean cycle time |
Infinite |
||
Decision Point(s) |
DP |
Objects leaving |
44.76 |
Final inventory (int. buff.) |
0.00 |
||
Mean inventory (int. buff.) |
0.00 |
||
Mean cycle time (int. buff.) |
0.00 |
||
Resource(s) |
|||
Mary |
Mean number in use |
11.12 |
Second order algebraic Model: