Suppose a random sample of 49 is selected from a population


Suppose a accidental exemplification of 49 is separated from a population delay a measure solution of 14. If the exemplification balance is 125, the 99% assurance season to cost the population balance is between ____________ .
120.00 and 130.00
119.85 and 133.15
119.85 and 130.15
119.85 and 135.15
118.00 and 132.00

A accidental exemplification of 49 separated from a population delay a measure solution of 14 yielded a balance = 125. The balance and the measure solution of the dispensation of the exemplification balances are ____________ .
125 and 2
125 and 49
120 and 2
125 and 1.33
125 and 14
For a accidental exemplification of 36 parts and a exemplification balance of 211, appraise a 95% assurance season for μ if the population measure solution is 23. Round the calculateer-arguments to 2 decimal places.
≤ μ ≤ .
The tolerance is +/­ 0.05
A accidental exemplification of capaciousness 70 is fascinated from a population that has a hostility of 49. The exemplification balance is 90.4. What is the purpose cost of μ? Erect a 94% assurance season for μ.
*Round your calculateer-arguments to 2 decimal places, the tolerance is +/­0.01.
The purpose cost of μ is .
The 94% assurance season: * ≤ μ ≤ *
Question 14
Use the subjoined instruction to erect the assurance seasons specific to cost μ.
a. 95% assurance for = 26, σ = 4.5, and n = 60
b. 98% assurance for = 117.6, σ = 26.89, and n = 75
c. 90% assurance for = 2.419, σ = 0.891, and n = 32
d. 80% assurance for = 53.7, σ = 13.1, N = 500, and n = 47
*Round your calculateer-argument to 2 decimal places, the tolerance is +/­0.01.

**Round your calculateer-argument to 3 decimal places, the tolerance is +/­0.001.
a. * ≤ μ ≤ *
b. * ≤ μ ≤ *
c. **≤ μ ≤ **
d. * ≤ μ ≤ *
A candy sodality fills a 20­ounce lot of Halloween candy delay partially wrapped pieces of candy. The enumerate of pieces of candy per lot varies accordingly the lot is sold by power. The sodality deficiencys to cost the enumerate of pieces per lot. Inspectors accidentally exemplification 120 lots of this candy and calculate the enumerate of pieces in each lot. They experience that the exemplification balance enumerate of pieces is 18.72. Assuming a population measure solution of .8735, what is the purpose cost of the enumerate of pieces per lot? Erect a 99% assurance season to cost the balance enumerate of pieces per lot for the population.
Round the calculateer-arguments to 2 decimal places.
Point Estimate
≤ μ ≤
The tolerance is +/­ 0.05.
The moderation aggregate dollar forfeiture at a quiet provision is hither than that at a supermarket. Despite weaker­ticket forfeitures, quiet provisions can stagnant be remunerative accordingly of the capaciousness of agency, quantity of vocation, and the markup. A investigationer is zealous in estimating the moderation forfeiture sum for quiet provisions in rural Long Island. To do so, she accidentally exemplificationd 24 forfeitures from separate quiet provisions in rural Long Island and tabulated the sums to the unswerving dollar. Use the subjoined postulates to erect a 90% assurance season for the population moderation sum of forfeitures. Assume that the population measure solution is 3.23 and the population is normally reserved.
$2
5
14
4

$11
4
7
1

$8
2
6
3

$7
1
3
6

$9
10
7
8

$3
8
2
4

Round the calculateer-arguments to 3 decimal places.
≤ μ ≤
The tolerance is +/­ 0.005.
In direct to erect a 90% assurance season for the population balance when the population measure solution σ is unrecognized and the exemplification of capaciousness n = 18, the embezzle t­rate to use is represented by ____________.
t 0.90, 18
t 0.05, 18
t 0.05, 17
t 0.10, 18
In direct to erect a 99% assurance season for the population balance when the population measure solution σ is unrecognized and the exemplification of capaciousness n = 20, the embezzle t­rate to use is represented by ____________.
t 0.01, 19
t 0.05, 19
t 0.005, 19

t 0.99, 20
The consideration t rate associated delay the excellent 5% of the t dispensation and 12 degrees of immunity is __________.
2.179
3.330
1.782
3.055
1.356
The consideration t rate associated delay the excellent 10% of the t dispensation and 23 degrees of immunity is __________.
1.714
1.319
1.321
2.069
2.332
A generally-known berth marketing resolute attempts towing affirmrs delay a mail hostilities that involves a controvert using berth stickers. Often when vulgar afsturdy to berths in this mode they indication up for multiple berth supplys. Suppose the marketing resolute deficiencys to cost the moderation enumerate of supplys per customer of those who forfeiture at last one supply. To do so, the marketing resolute’s investigationer accidentally selects 65 returned controvert entries. Twenty­seven hold supply requests. Of the 27, the moderation enumerate of supplys is 2.10, delay a measure solution of .86. The investigationer uses this instruction to appraise a 98% assurance season to
cost and assumes that x is normally reserved. What does the investigationer experience?
Round the calculateer-arguments to 2 decimal places.
≤ μ ≤
The tolerance is +/­ 0.05.
According to a balancelook by Topaz Enterprises, a tramp auditing sodality, the moderation hallucination by tramp delegates is $128. Suppose this form was succeeded from a accidental exemplification of 41 tramp delegates and the exemplification measure solution is $21. What is the purpose cost of the generally-known moderation hallucination for all tramp delegates? Appraise a 98% assurance season for the generally-known moderation hallucination established on these exemplification results. Assume the tramp delegate hallucinations are normally reserved in the population. How broad is the season? Interpret the season.
Round the calculateer-arguments to 3 decimal places where needful.
Point Cost = $ .
≤ μ ≤
Interval Width =
The tolerance is +/­ 0.005.
A accidental exemplification of 15 parts is fascinated, submissive a exemplification balance of 2.364 delay a exemplification hostility of .81. Assume x is normally reserved and erect a 90% assurance season for the population balance. Round the calculateer-arguments to 3 decimal places.
≤ μ ≤
The tolerance is +/­ 0.005.

According to Runzheimer International, the moderation require of a private taunt for vocation trampers in the financial activity is $1,250. Suppose another tramp activity investigation sodality assumes a accidental exemplification of 51 vocation trampers in the financial activity and states that the exemplification moderation require of a private taunt is $1,192, delay a exemplification measure solution of $279. Erect a 98% assurance season for the population balance from these exemplification postulates. Assume that the postulates are normally reserved in the population. Now go end and search the $1,250 form published by Runzheimer International. Does it decline into the assurance season appraised from the exemplification postulates? What
does it report you?
Round your calculateer-arguments to 2 decimal places, the tolerance is +/­0.01.
The 98% assurance season: ≤ μ ≤
The form dedicated by Runzheimer Intergenerally-known declines (beyond or internally) the assurance season. Therefore, there is no
reason to exclude the Runzheimer form as unanalogous from what we are getting established on this exemplification.
According to a balancelook by Runzheimer International, the moderation require of a fast­food asceticism (quarter­pound
cheeseburger, capacious fries, moderation glossy drain, save taxes) in Seattle is $4.82. Suppose this form was established on a exemplification of 27 unanalogous establishments and the measure solution was $0.37. Erect a 95% assurance season for the population balance require for all fast­food asceticisms in Seattle. Assume the requires of a fast­food asceticism in Seattle are normally reserved. Using the season as a pilot, is it slight that the population balance is indeed $4.50? Why or why not?
Round the calculateer-arguments to 4 decimal places.
≤ μ ≤
Since 4.50 in the season, we are 95% assured that μ 4.50.
The tolerance is +/­ 0.0005.
Assuming x is normally reserved, use the subjoined instruction to appraise a 90% assurance season to cost .
313
321

320
329

319
317

340
311

325
307

310
318

Round the calculateer-arguments to 2 decimal places.
≤ μ ≤
The tolerance is +/­ 0.05.
The marketing ruler of a capacious function provision deficiencys to cost the moderation enumerate of customers who invade the provision perfect five minutes. She accidentally selects five­minute seasons and calculates the enumerate of arrivals at the provision.
She succeeds the forms 54, 32, 41, 44, 56, 80, 49, 29, 32, and 74. The analyst assumes the enumerate of arrivals is normally reserved. Using these postulates, the analyst appraises a 95% assurance season to cost the balance rate for all five­minute seasons. What season rates does she get?
Round the comprised rates to 2 decimal places. Round your calculateer-arguments to 2 decimal places, the tolerance is +/­0.01.
≤ μ ≤
A meat­processing sodality in the Midwest produces and markets a lot of prospect weak sahabit sandwiches. The work is generally-knownly reserved, and the sodality is zealous in discerning the moderation vend cost charged for this part in provisions across the calculatery. The sodality cannot exonerate a generally-known census to breed this instruction. Established on the sodality instruction system’s roll of all venders who heave the work, a investigationer for the sodality contacts 36 of these venders and ascertains the selling costs for the work. Use the subjoined cost postulates and a population measure solution of 0.113 to state a purpose cost for the generally-known vend cost of the work.
Construct a 90% assurance season to cost this cost.

$2.23
2.16
2.12
2.01
1.99
2.23

$2.11
2.31
2.07
2.24
1.87
2.10

$2.12
1.98
2.17
2.18
2.09
2.08

$2.20
2.17
2.30
2.18
2.22
2.05

$2.17
2.14
2.29
2.32
2.15
2.16

$2.10
1.82
2.19
2.02
2.19
2.26

Round the calculateer-arguments to 3 decimal places.
Point Estimate
≤ μ ≤
The tolerance is +/­ 0.005.
A bank administrator deficiencys to state the sum of the moderation aggregate monthly deposits per customer at the bank. He appreciates an cost of this moderation sum using a assurance season is qualified. How capacious a exemplification should he assume to be delayin $200 the real moderation delay 99% assurance? He assumes the measure solution of aggregate monthly deposits for all customers is about $1,000.
Round your calculateer-argument up to the unswerving integer.
Sample .
The tolerance is +/­ 1.
Suppose you entertain been subjoined a point airline hoard for numerous years. You are zealous in determining the moderation daily cost of this hoard in a 10­year era and you entertain appropinquation to the hoard reports for these years. However, you do not deficiency to moderation all the daily costs balance 10 years accordingly there are separate thousand postulates purposes, so you flow to assume a accidental exemplification of the daily costs and cost the moderation. You deficiency to be 90% assured of your results, you deficiency the cost to be delayin $3.00 of the penny moderation, and you appreciate the measure solution of the cost of this hoard is about $12.75 balance this era of date. How capacious a exemplification should you assume?
Sample capaciousness =
A generally-known embellishment salon compact deficiencys to cost the enumerate of dates per year a woman has her hair executed at a embellishment salon if she uses one at last uniformly a year. The compact’s investigationer costs that, of those women who use a embellishment salon at last uniformly a year, the measure solution of enumerate of dates of habit is approximately 6. The generally-known compact deficiencys the cost to be delayin one date of the real balance rate. How capacious a exemplification should the investigationer assume to succeed a 98% assurance plane?
Round your calculateer-argument up to the unswerving integer.
Sample .
The tolerance is +/­ 1.