# Multiple choices | Mathematics homework help

1.      In a poll, respondents were asked whether they had constantly been in a car clothing. 220 respondents indicated that they had been in a car clothing and 370 respondents said that they had not been in a car clothing. If one of these respondents is fortuityly separated, what is the likelihood of getting someone who has been in a car clothing? Round to the unswerving thousandth.A. 0.384 B. 0.380 C. 0.373D. 0.370

P(accident) = 220 / (220 + 370) = 0.373

2.      If you flip a invent three eras, the likely issues are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the likelihood of getting at averageest one crown?

A. 4/9                          B. 5/6                 C. 7/8           D. 5/8

P(at averageest one crown) = (Number of unions delay one or over H) / (Total                                                                     enumerate of unions)

P(at averageest one crown) = 7 / 8

3.      Joe negotiatet 20 cards from a banner 52-card marshal, and the enumerate of red cards exceeded the enumerate of sombre cards by 8. He reshuffled the cards and negotiatet 30 cards. This era, the enumerate of red cards exceeded the enumerate of sombre cards by 10. Individualize which negotiate is closer to the 50/50 association of red/sombre wait-fored of untarnishedly negotiatet hands from a untarnished marshal and why.

A. The pristine sequence is closer accordingly 1/10 is farther from 1/2 than is 1/8.

B. The sequence closer to the presumptive 50/50 cannot be stable reasonable the enumerate of red and sombre cards for each negotiate is ardent.

C. The assist sequence is closer accordingly 20/30 is closer to 1/2 than is 14/20.

D. The pristine sequence is closer accordingly the estrangement betwixt red and sombre is trivialer than the estrangement in the assist sequence.

1st negotiate: 14 red and 6 sombre     P(red) = 14/20 = 0.70

2nd negotiate: 20 red and 10 sombre  P(red) = 20/30 = 0.67 < 0.70

4.      Suppose you possess an extremely ununtarnished die: The likelihood of a 6 is 3/8, and the likelihood of each other enumerate is 1/8. If you throw the die 32 eras, how numerous twos do you wait-for to see?A. 2                        B. 4                            C. 3                             D. 5

E(2) = np = 32(1/8) = 4

5.      A assort consists of 50 women and 82 men. If a tyro is fortuityly separated, what is the likelihood that the tyro is a mother?

A. 32/132 B. 25/66C. 50/132          D. 82/132

P(woman) = 50 / (50 + 82) = 50/132 = 25/66

6.      If you flip a invent three eras, the likely issues are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the likelihood that at averageest two crowns supervene orderlyly?

A. 1/8          B. 3/8           C. 5/8       D. 6/8

P(two orderly H) = (Number of unions delay HH) / (Total enumerate of                                                                  combinations)

P(two orderly H) = 3/8

7.      Suppose you buy 1 ticket for \$1 out of a lottery of 1000 tickets where the ovation for the one seductive ticket is to be \$500. What is your wait-fored treasure?

A. \$0.00       B. −\$0.40       C. −\$1.00        D. −\$0.50

E(x) = (1/1000)(\$500) – 1 = \$0.50 - \$1 = -\$0.50

8.      If you flip a invent three eras, the likely issues are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the likelihood of getting at averageest two tails?

A. 1/2        B. 2/3           C. 3/4        D. 4/9

P(at averageest 2 T) = (Number of unions delay 2 or over T) / (Total enumerate

of unions)

P(at averageest 2 T) = 4/8 = ½

9.      A bag contains lewd remnants of which one is red, one is sky sky cerulean-colored-colored, one is bleak, and one is yellow. A remnant is separated at fortuity from the bag and then replaced in the bag. A assist remnant is then separated at fortuity. Execute a schedule of the likely issues (for pattern, RB plays the issue red remnant followed by sky sky sky sky cerulean-colored-colored-colored remnant) and use your schedule to individualize the likelihood that the two remnants separated are the same hue. (Hint: There are 16 likely issues.)A. 1/4         B. ¾     C. 2/16       D. 3/16

Possible issues:                  RR       RB       RG      RY

BR       BB       BG      BY

GR      GB      GG      GY

YR      YB      YG      YY

P(two of same hue) = (Number of unions delay same hue) / (Total

enumerate of unions)

P(two of same hue) = 4/16 = ¼

10.  A committee of three nation is to be formed. The three nation conquer be separated from a schedule of five likely committee limbs. A unadorned fortuity pattern of three nation is captured, delayout regaining, from the clump of five nation. Using the letters A, B, C, D, E to play the five nation, schedule the likely patterns of bulk three and use your schedule to individualize the likelihood that B is interjacent in the pattern. (Hint: There are 10 likely patterns.)A. 0.6         B. 0.4         C. 0.7      D. 0.8

Sample space:              ABC    ABD   ABE    ACD   ACE

P(union includes B) = (Number of unions including B) / (Total

enumerate of unions)

P(union includes B) = 6/10 = 0.6

11.  In the pristine sequence of rolls of a die, the enumerate of odd enumerates exceeded the enumerate of equal enumerates by 5. In the assist sequence of rolls of the same die, the enumerate of odd enumerates exceeded the enumerate of equal enumerates by 11. Individualize which sequence is closer to the 50/50 association of odd/equal wait-fored of a untarnishedly rolled die.

A. The assist sequence is closer accordingly the estrangement betwixt odd and equal enumerates is senior than the estrangement for the pristine sequence.

B. The pristine sequence is closer accordingly the estrangement betwixt odd and equal enumerates is near than the estrangement for the assist sequence.

C. Since 1/2 > 1/5 > 1/11, the pristine sequence is closer.

D. The sequence closer to the presumptive 50/50 cannot be stable reasonable the whole enumerate of rolls for twain sequence is ardent.

12.  Jody checked the region 12 eras on Monday, and the ultimate digit of the region was odd six eras over than it was equal. On Tuesday, she checked it 18 eras and the ultimate digit was odd eight eras over than it was equal. Individualize which sequence is closer to the 50/50 association of odd/equal wait-fored of such a sequence of region checks.

A. The Monday sequence is closer accordingly 1/6 is closer to 1/2 than is 1/8.

B. The Monday sequence is closer accordingly 6/12 is closer to 0.5 than is 8/18.

C. The Tuesday sequence is closer accordingly the 13/18 is closer to 0.5 than is 9/12.

D. The sequence closest to the presumptive 50/50 cannot be stable delayout penetrating the enumerate of odds and equals in each sequence.

Monday: 9 odd, 3 equal           P(odd) = 9/12 = 0.75

Tuesday: 13 odd, 5 equal         P(odd) = 13/18 ≈ 0.722 < 0.75

13.  Suppose you pay \$1.00 to roll a untarnished die delay the intelligence that you conquer get tail \$3.00 for rolling a 5 or a 2, pin otherwise. What is your wait-fored treasure?

A. \$1.00           B. \$0.00              C. \$3.00        D. −\$1.00

E(x) = (1/3)(\$3) - \$1 = \$1 - \$1 = \$0

14.  On a multiple excellent trial, each inquiry has 6 likely exculpations. If you execute a fortuity suspect on the pristine inquiry, what is the likelihood that you are reform?

A. 1/5         B. 1/6         C. 1/4        D. 2/5

P(correct) = Enumerate of reform exculpations / Enumerate of likely excellents

P(correct) = 1/6

15.  A consider of two types of exterminate killers was produced on two same exterminate frames. One exterminate killer killed 15% over exterminates than the other. This estrangement was telling at the 0.05 roll. What does this average?

A. The proficiency was due to the deed that there were over exterminates in one consider.

B. The likelihood that the estrangement was due to fortuity over is senior than 0.05.

C. The likelihood that one exterminate killer effected rectify by fortuity over is near than 0.05.

D. There is not ample counsel to execute any blank.

16.  The classification of B.A. rates acquired by a topical garden is scheduleed under, by elder.

Major                    Frequency

English                 2073

Mathematics        2164

Chemistry            318

Physics                856

Liberal Arts          1358

Engineering          868

9313

What is the likelihood that a fortuityly separated rate is not in Business?

A. 0.7800          B. 0.8200         C. 0.8300         D. 0.9200

P(not in Business) = (Number not in Business) / Whole enumerate of rates

P(not in Business) = (9313 – 1676) / 9313

17.  A 28-year-old man pays \$125 for a one-year career insurance cunning delay coverage of \$140,000. If the likelihood that he conquer feed through the year is 0.9994, to the unswerving dollar, what is the man’s wait-fored treasure for the insurance cunning?

A. \$139,916        B. −\$41         C. \$84         D. −\$124

E(x) = (1 – 0.9994)(\$140,000) - \$125 = -\$41

18.  A bag contains 4 red marbles, 3 sky sky sky sky cerulean-colored-colored-colored marbles, and 7 bleak marbles. If a marble is fortuityly separated from the bag, what is the likelihood that it is sky sky cerulean-colored-colored?

A. 2/11        B. 3/11       C. 5/14        D. 3/14

P(blue) = Enumerate of sky sky sky sky cerulean-colored-colored-colored marbles / Whole enumerate of marbles

P(blue) = 3 / (4 + 3 + 7) = 3/14

19.  The grounds set plays the allowance rolls of the limbs of a dominion club. Revere the likelihood that a fortuityly separated limb earns at averageest \$98,000.

112,000 126,000 90,000 133,000 94,000 112,000 98,000 82,000 147,000 182,000 86,000 105,000

140,000 94,000 126,000 119,000 98,000 154,000 78,000 119,000

A. 0.4         B. 0.6        C. 0.66         D. 0.7

P(stipend ≥ \$98,000) = Enumerate of salaries ≥ 98,000 / Whole enumerate of salaries

P(stipend ≥ \$98,000) = 14/20 = 0.7

20.  A consider of tyros preamble Statistics 101 was produced. Lewd hundred tyros who learned for over than 10 hours averaged a B. Two hundred tyros who learned for near than 10 hours averaged a C. This estrangement was telling at the 0.01 roll. What does this average?

A. The likelihood that the estrangement was due to fortuity over is senior than 0.01.

B. There is near than a 0.01 fortuity that the pristine clump’s removes were rectify by fortuity over.

C. The proficiency was due to the deed that over nation learned.

D. There is not ample counsel to execute any blank

21.  Sample bulk = 400, pattern average = 44, pattern banner flexion = 16. What is the extremity of untruth?

A. 1.4               B. 1.6               C. 2.2             D. 2.6

Assuming a 95% reliance roll, and noting that this assort seems to use  z = 2     for this reliance roll instead of the over deferential 1.96 treasure.

E = z*s/√n = 2 * 16 / √400 = 1.6

22.  Select the best fit frequentedion on the plant diagram under. D. None of the frequentedions is the frequentedion of best

23.              A researcher wishes to revere the average total of capital departed per month on prop by households in a actual neighborhood. She desires a extremity of untruth of \$30. Past studies hint that a population banner flexion of \$248 is cool. Revere the insufficiency pattern bulk needed to revere the population average delay the methodic exactness.

A. 274        B. 284      C. 264        D. 272

Again, grand a 95% reliance cessation, delay z = 2.00 instead of 1.96:

n = (z * s / E)2 = (2 * 248 / 30)2 = 273.35 à 274

24.           Suggest the object of the apposition inchoate the grounds. The graph demonstrations force of coffee (y) and enumerate of scoops used to execute 10 cups of coffee (x). Identify the reasonable object of the apposition.

A. The change in the x changeable is a frequented object of the change in the y changeable.

B. There is no apposition betwixt the changeables.

C. The apposition is due to a low underlying object.

D. The apposition betwixt the changeables is inventcidental

25.  Suggest the object of the apposition inchoate the grounds. The graph demonstrations force of coffee (y) and enumerate of scoops used to execute 10 cups of coffee (x). Identify the reasonable object of the apposition.

 A.The change in the x changeable is a frequented object of the change inthe y changeable. B. There is no apposition betwixt the changeables. C. The apposition is due to a low underlying object. D. The apposition betwixt the changeables is inventcidental.

26.A population adaptation is to be revered. Revere the insufficiency pattern bulk needed to finish a extremity of untruth E = 0.01delay a 95% rate of reliance.

A. 7,000           B. 8,000              C. 9,000       D. 10,000

n = p(1-p)(z/E)2 = (0.5)(0.5)(2/0.01)2 = 10,000

27. Select the best revere of the apposition coefficient for the grounds depicted in the plant diagram. A. -0.9

B. 0.1

C. 0.5

D. 0.9

The arise of the return frequentedion is indirect, so the coefficient of apposition must

also be indirect.

28. A pattern of nine tyros is separated from inchoate the tyros preamble a feature exam. The nine tyros were asked how plenteous era they had departed considering for the exam and the responses (in hours) were as follows:18, 7, 10, 13, 12, 16, 5, 20, 21

Estimate the average consider era of all tyros preamble the exam. Round your exculpation to the unswerving tenth of an hour if requisite.     A. 13 hours     B. 12.2 hours         C. 13.6 hours

D. It is not likely to revere the population average from this pattern grounds

Mean = (18 + 7 + 10 + 13 + 12 + 16 + 5 + 20 + 21) / 9 = 13.6

29. The plant frame and best-fit frequentedion demonstration the homogeneity inchoate the grounds for the worth of a hoard (y) and avocation (x) in absolute units. The apposition coefficient is 0.8. Forebode the hoard worth for an avocation treasure of 6. A. 8.8

B. 6.2

C. 8.2

D. None of the treasures are reform

Draw a perpendicular frequentedion through “6” on the downright axis, and stretch the frequentedion perpendicularly until it intersects the frequentedion on the graph. Then inhale a downright frequentedion through the top of intersection and stretch that frequentedion to the left until it intersects the perpendicular axis. Unravel the treasure from the perpendicular axis, which is about 6.2.

30.The graph demonstrations a rate of association (y) and miles walked weekly. Identify the reasonable object of the apposition. A. The apposition is inventcidental.

B. There is a low underlying object of the apposition.

C. There is no apposition betwixt the changeables.

D. Walking is a frequented object of the association.

31. Elequal effeminate garden tyros are separated at fortuity and asked their apexs. The apexs (in inches) are as follows:67, 59, 64, 69, 65, 65, 66, 64, 62, 64, 62Estimate the average apex of all effeminate tyros at this garden. Round your exculpation to the unswerving tenth of an inch if requisite.

A. It is not likely to revere the population average from this pattern grounds

B. 64.3 inches

C. 64.9 inches

D. 63.7 inches

Mean = (67 + 59 + 64 + 69 + 65 + 65 + 66 + 64 + 62 + 64 + 62) / 11 = 64.3

32. Select the best fit frequentedion on the plant diagram under. A. A

B. B

C. C

D. All of the frequentedions are equivalent good

33. In a poll of 400 patrons in a actual recite, 61% said that they contrariant a patron ID account that influence over some licit patrons from voting. The extremity of untruth in the poll was reported as 4 percentage tops (delay a 95% rate of reliance). Which recitement is reform?

A. The reported extremity of untruth is accordant delay the pattern bulk.

B. There is not ample counsel to individualize whether the extremity of untruth is accordant delay the pattern bulk.

C. The pattern bulk is too trivial to finish the methodic extremity of untruth.

D. For the ardent pattern bulk, the extremity of untruth should be trivialer than methodic

Required pattern bulk = (phat)(1 – phat)(z/E)2 = (0.61)(1 – 0.61)(2/0.04)2 = 594.75

34.The plant frame and best-fit frequentedion demonstration the homogeneity inchoate the enumerate of cars cessation by a develop (y) and the total of era behind the end of assortes (x) in absolute units. The apposition coefficient is -0.55. Individualize the total of change in the enumerate of cars not explained by the change era behind sch A. 55%

B. 70%

C. 30%

D. 45%

Coefficient of non-favor = 1 – r2 = 1 – (-0.55)2 = 0.6975 → 70%

35. Which graph has two clumps of grounds, appositions delayin each clump, but no apposition inchoate all the grounds?

A. B. C. D 36. The plant frame and best-fit frequentedion demonstration the homogeneity inchoate the enumerate of cars cessation by a develop (y) and the total of era behind the end of assortes (x) in absolute units. The apposition coefficient is -0.55. Use the frequentedion of best fit to forebode the enumerate of cars at era 4 behind the end of assortes. A. 7.0

B. 6.0

C. 8.0

D. 3.5

Draw a perpendicular frequentedion through the treasure 4 on the downright axis and stretch the frequentedion perpendicularly until it intersects the frequentedion demonstrationn on the graph. Then inhale a downright frequentedion through the top of intersection and stretch it to the left until it intersects the perpendicular axis. Unravel the treasure where the downright frequentedion crosses the perpendicular axis. The treasure is almost 7.

37. A researcher wishes to revere the adaptation of garden tyros who deception on exams. A poll of 560 garden tyros demonstrationed that 27% of them had, or intended to, deception on examinations. Find the 95% reliance cessation.

A. 0.2323 to 0.3075

B. 0.2325 to 0.3075

C. 0.2325 to 0.3185

D. 0.2323 to 0.3185

Lower designation = phat – z*sqrt(phat*(1 – phat)/n)

Lower designation = 0.27 – 2*sqrt(0.27*0.73/560)

Lower designation = 0.2325

Upper designation = phat+ z*sqrt(phat*(1 – phat)/n)

Upper designation = 0.27 + 2*sqrt(0.27*0.73/560)

Upper designation = 0.3075

38. Inchoate a fortuity pattern of 150 employees of a feature concourse, the average substitute interspace is 29.6 miles. This average lies 1.2 banner flexions over the average of the sampling classification. If a assist pattern of 150 employees is separated, what is the likelihood that for the assist pattern, the average substitute interspace conquer be near than 29.6 miles?

A. 0.8849           B. 0.5          C. 0.1131        D. 0.1151

P(assist pattern average ≤ 29.6) = P(z ≤ 1.2) = 0.8849

39. The plant frame and best-fit frequentedion demonstration the homogeneity betwixt the worth per item (y) and the availability of that item (x) in absolute units. The apposition coefficient is -0.95. Individualize the total of change in pricing explained by the change in availability. A. 5% B. 10% C. 95% D. 90%     Coefficient of favor = r2 = (-0.95)2 = 0.9025 ≈ 90% 40. Of the 6796 tyros in one develop purlieus, 1537 cannot unravel up to remove roll. Inchoate a pattern of 812 of the tyros from this develop purlieus, 211 cannot unravel up to remove roll. Find the pattern adaptation of tyros who cannot unravel up to remove roll       A. 0.14        B. 0.26      C. 211      D. 0.23 phat = x/n = 211 / 812 = 0.26