# Assume that the data has a normal distribution

Question 1

1.

Assume that the basis has a recognized division and the deem of observations is superior than fifty. Invent the discriminating z esteem used to test a void theory. = 0.09 for a right-tailed test.

Answer

±1.96

1.34

±1.34

1.96

5 points

Question 2

1.

Find the esteem of the test statistic z using z = The right is that the adaptation of drowning deaths of progeny ascribable to beaches is further than 0.25, and the exemplification statistics involve n = 681 drowning deaths of progeny delay 30% of them ascribable to beaches.

Answer

3.01

2.85

-2.85

-3.01

5 points

Question 3

1.

Use the absorbed notice to invent the P-value. Also, use a 0.05 notion smooth and declare the omission encircling the void theory (exclude the void theory or lose to exclude the void theory). The test statistic in a left-tailed test is z = -1.83.

Answer

0.0672; exclude the void theory

0.0336; exclude the void theory

0.9664; lose to exclude the void theory

0.0672; lose to exclude the void theory

5 points

Question 4

1.

Use the absorbed notice to invent the P-value. Also, use a 0.05 notion smooth and declare the omission encircling the void theory (exclude the void theory or lose to exclude the void theory). Delay H1: p < 3/5, the test statistic is z = -1.68.

Answer

0.093; lose to exclude the void theory

0.0465; lose to exclude the void theory

0.0465; exclude the void theory

0.9535; lose to exclude the void theory

5 points

Question 5

1.

Formulate the involved omission in nontechnical stipulations. Be safe to oration the primary right. The possessor of a football team rights that the average apparatus at games is aggravate 694, and he is hence justified in tender the team to a city delay a larger stadium. Assuming that a theory test of the right has been conducted and that the omission is loseure to exclude the void theory, declare the omission in nontechnical stipulations.

Answer

There is not competent proof to aid the right that the average apparatus is hither than 694.

There is competent proof to aid the right that the average apparatus is superior than 694.

There is competent proof to aid the right that the average apparatus is hither than 694.

There is not competent proof to aid the right that the average apparatus is superior than 694.

5 points

Question 6

1.

Assume that a theory test of the absorbed right allure be conducted. Identify the sign I or sign II deception for the test. A consumer vindication order rights that the average mileage for the Carter Motor Company's new sedan is hither than 32 miles per gallon. Identify the sign I deception for the test.

Answer

Fail to exclude the right that the average is homogeneous to 32 miles per gallon when it is in-effect superior than 32 miles per gallon.

Reject the right that the average is homogeneous to 32 miles per gallon when it is in-effect hither than 32 miles per gallon.

Reject the right that the average is homogeneous to 32 miles per gallon when it is in-effect 32 miles per gallon.

Fail to exclude the right that the average is homogeneous to 32 miles per gallon when it is in-effect hither than 32 miles per gallon.

5 points

Question 7

1.

Find the P-esteem for the involved theory test. In a exemplification of 88 progeny clarified unpremeditatedly from one town, it is base that 8 of them let from asthma. Invent the P-esteem for a test of the right that the adaptation of all progeny in the town who let from asthma is homogeneous to 11%.

Answer

0.2843

-0.2843

0.2157

0.5686

5 points

Question 8

1.

Find the P-esteem for the involved theory test. An period in a chronicle announces that 34% of American fathers transfer no function for branch foresight. A researcher rights that the likeness is excellent for fathers in the town of Littleton. A unpremeditated exemplification of 225 fathers from Littleton, yielded 97 who did not succor delay branch foresight. Invent the P-esteem for a test of the researcher's right.

Answer

0.0019

0.0015

0.0038

0.0529

5 points

Question 9

1.

Find the discriminating esteem or esteems of based on the absorbed notice. H1: > 3.5 n = 14 = 0.05

Answer

22.362

5.892

24.736

23.685

5 points

Question 10

1.

Find the discriminating esteem or esteems of based on the absorbed notice. H1: > 26.1 n = 9 = 0.01

Answer

1.646

21.666

20.090

2.088

5 points

Question 11

1.

Find the deem of successes x hinted by the absorbed declarement. A computer creator unpremeditatedly selects 2850 of its computers for character arrogance and invents that 1.79% of these computers are base to be deficient.

Answer

5 points

Question 12

1.

Assume that you contrivance to use a notion smooth of alpha = 0.05 to test the right that p1 = p2, Use the absorbed exemplification sizes andgum of successes to invent the pooled deem Round your counterpart to the unswerving thousandth. n1 = 570;n2 = 1992 x1 = 143;x2 = 550

Answer

0.541

0.270

0.520

0.216

5 points

Question 13

1.

Assume that you contrivance to use a notion smooth of alpha = 0.05 to test the right that p1 = p2. Use the absorbed exemplification sizes and deems of successes to invent the z test statistic for the theory test. A announce on the gloomy information dispersed declared that 10 out of 108 households delay pet dogs were burglarized and 20 out of 208 delayout pet dogs were burglarized.

Answer

z = -0.041

z = -0.102

z = 0.000

z = -0.173

5 points

Question 14

1.

Solve the amount. The consideration shows the deem of smokers in a unpremeditated exemplification of 500 adults olden 20-24 and the deem of smokers in a unpremeditated exemplification of 450 adults olden 25-29. Pretend that you contrivance to use a notion smooth of alpha = 0.10 to test the right that Find the discriminating esteem(s) for this theory test. Do the basis yield competent proof that the adaptation of smokers in the 20-24 age order is unanalogous from the adaptation of smokers in the 25-29 age order?

Answer

z = ± 1.645; yes

z = ± 1.28; yes

z = ± 1.96; no

z = 1.28; no

5 points

Question 15

1.

Assume that you contrivance to use a notion smooth of alpha = 0.05 to test the right that p1 = p2. Use the absorbed exemplification sizes and deems of successes to invent the P-esteem for the theory test. n1 = 50;n2 = 75 x1 = 20;x2 = 15

Answer

0.0032

0.0146

0.1201

0.0001

5 points

Question 16

1.

Construct the involved dependence period for the dissimilitude among population adaptations p1 - p2. Pretend that the exemplifications are recalcitrant and that they keep been unpremeditatedly clarified. x1 = 61, n1 = 105 and x2 = 82, n2 = 120; Construct a 98% dependence period for the dissimilitude among population adaptations p1 - p2.

Answer

0.456 < p1 - p2 < 0.707

0.432 < p1 - p2 < 0.730

-0.228 < p1 - p2 < 0.707

-0.252 < p1 - p2 < 0.047

5 points

Question 17

1.

Construct the involved dependence period for the dissimilitude among the two population averages. Pretend that the two exemplifications are recalcitrant unmixed unpremeditated exemplifications clarified from recognizedly as sorted populations. Do not pretend that the population test deviations are homogeneous. A researcher was animated in comparing the subject pulse rebukes of fellow-creatures who practice constantly and the pulse rebukes of fellow-creatures who do not practice constantly. She obtained recalcitrant unmixed unpremeditated exemplifications of 16 fellow-creatures who do not practice constantly and 12 fellow-creatures who do practice constantly. The subject pulse rebukes (in beats per searching) were chronicled and the digest statistics are as follows. Construct a 95% dependence period for mu1 - mu2, the dissimilitude among the average pulse rebuke of fellow-creatures who do not practice constantly and the average pulse rebuke of fellow-creatures who practice constantly.

Answer

-3.22 beats/min < mu1 - mu2 < 11.62 beats/min

-3.55 beats/min < mu1 - mu2 < 11.95 beats/min

-3.74 beats/min < mu1 - mu2 < 12.14 beats/min

-4.12 beats/min < mu1 - mu2 < 14.72 beats/min

5 points

Question 18

1.

State what the absorbed dependence period hints encircling the two population averages. A researcher was animated in comparing the climaxs of women in two unanalogous countries. Recalcitrant unmixed unpremeditated exemplifications of 9 women from state A and 9 women from state B yielded the subjoined climaxs (in inches). The subjoined 90% dependence period was obtained for mu1 - mu2, the dissimilitude among the average climax of women in state A and the average climax of women in state B.-4.34 in. < mu1 - mu2 < -0.03 in What does the dependence period hint encircling the population averages?

Answer

The dependence period involves solely indirect esteems which hints that the average climax of women from state A is superior than the average climax of women from state B.

The dependence period involves solely indirect esteems which hints that the two population averages potentiality be homogeneous. There doesn't answer to be a weighty dissimilitude among the average climax of women from state A and the average climax of women from state B.

The dependence period involves solely indirect esteems which hints that the average climax of women from state A is smaller than the average climax of women from state B.

The dependence period involves 0 which hints that the two population averages potentiality be homogeneous. There doesn't answer to be a weighty dissimilitude among the average climax of women from state A and the average climax of women from state B.

5 points

Question 19

1.

Construct the involved dependence period for the dissimilitude among the two population averages. Pretend that the two exemplifications are recalcitrant unmixed unpremeditated exemplifications clarified from recognizedly as sorted populations. Also pretend that the population test deviations are homogeneous (sigma1 = sigma2), so that the test deception of the dissimilitude among averages is obtained by pooling the exemplification variances. A tint creator wanted to collate the arefaction periods of two unanalogous signs of tint. Recalcitrant unmixed unpremeditated exemplifications of 11 cans of sign A and 9 cans of sign B were clarified and applied to homogeneous surfaces. The arefaction periods, in hours, were chronicled. The digest statistics are as follows. Construct a 99% dependence period for mu1 - mu2, the dissimilitude among the average arefaction period for tint sign A and the average arefaction period for tint sign B.

Answer

-2.73 hrs < mu1 - mu2 < 7.73 hrs

-0.64 hrs < mu1 - mu2 < 5.64 hours

-1.50 hrs < mu1 - mu2 < 6.50 hrs

-2.01 hrs < mu1 - mu2 < 7.01 hrs

5 points

Question 20

1.

The two basis sets are trusting. Invent to the unswerving tenth.

Answer

44.1

20.3

33.9

203.4