Show that by integrating the Maxwell–Boltzmann probability distribution N(E) = N {(m k / / p)(2 T)..


Show that by integrating the Maxwell–Boltzmann probability distribution N(E) = N {(m k / / p)(2 T) }3 Ee– E/kT where the middle energy is dened by   = Nò (E)EdE/N,N is the aggregate enumerate of mites, and the limits of integration are from E = 0 to E = ∞ that the middle energy of a mite that follows this distribution is = 3/2 kT.