· Respond to your classmates’ posts in at least
2
5 words.
PEERS RESPONSE:
I was assigned number
4
2, for solving the problems
3
from page 7
0
8 and 3 from page 7
1
9
.
Problem 3 from Page 708.
f(x)=2x−1.
The function of this equation is (x)=2x−1.
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. Domain: (−∞, ∞). The range is a set of all valid y values: Range (−∞, ∞).
The relation is a set of ordered pairs of the x and y intercepts. This passes the Vertical Line Test because, all x values have a single y value.
|
x |
f(x)=2x−1 |
y |
|||
|
1/2 |
2(1/2) -1 |
0 | |||
|
2(0)-1 |
-1 | ||||
| 1 |
2(1)-1 |
||||
|
-1/2 |
2(-1/2)-1 |
-2 |
Problem 3 from Page 719
f(x) = (x − 3)2
For the Horizontal Transformation of this equation since any real number can be used to replace x in (x − 3)2, the domain is (−∞, ∞). And since the graph continues up from (3, 0), the range is [0, ∞).
|
f(x) = (x-3)^2 |
|
| 3 |
(3-3)^2 |
| 2 |
(2-3)^2 |
|
(1-3)^2 |
4 |
|
(-3-3)^2 |
9 |
-Angela
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